y^2-28y+490=0

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Solution for y^2-28y+490=0 equation:


Simplifying
y2 + -28y + 490 = 0

Reorder the terms:
490 + -28y + y2 = 0

Solving
490 + -28y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-490' to each side of the equation.
490 + -28y + -490 + y2 = 0 + -490

Reorder the terms:
490 + -490 + -28y + y2 = 0 + -490

Combine like terms: 490 + -490 = 0
0 + -28y + y2 = 0 + -490
-28y + y2 = 0 + -490

Combine like terms: 0 + -490 = -490
-28y + y2 = -490

The y term is -28y.  Take half its coefficient (-14).
Square it (196) and add it to both sides.

Add '196' to each side of the equation.
-28y + 196 + y2 = -490 + 196

Reorder the terms:
196 + -28y + y2 = -490 + 196

Combine like terms: -490 + 196 = -294
196 + -28y + y2 = -294

Factor a perfect square on the left side:
(y + -14)(y + -14) = -294

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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